Chemistry, asked by science5929, 1 year ago

The specific heat of a mixture of two gases at constant volume is 13r/6 the ratio of number of moles of 1st gas to 2nd gas is 1:2, the respective gas may be

Answers

Answered by ChiragMeher
0
Given a mixture with One mole of a monoatomic ideal gas is mixed with two moles of a diatomic gas.

The specific heat of the mixture =C=1×C1+2×C23==C=1×C1+2×C23=1×3R2+2×5R231×3R2+2×5R23=2.17R


Similar questions