Physics, asked by harshgoyal327, 1 year ago

The specific heat of Argon at constant volume
is 0.3122k.J/kg/K. Find the specific heat of
Argon at constant pressure if R=8.314 kJ/k
mole K. (Molecular weight of argon =
39.95)

1) 5203 2) 5302
3) 2305. 4)3025

Answers

Answered by anatarajan1969
1

It is tungsten not argon

Ok


harshgoyal327: this is argon gas not tungsten
Answered by CarliReifsteck
2

Answer:

The specific heat of  argon at constant pressure is 0.5203 kJ/kg K.

Explanation:

Given that,

Specific heat of argon = 0.3122 kJ/kg/K

Molecular weight of argon = 39.95

We need to calculate the specific heat of  argon at constant pressure

Using formula of specific heat

c_{p}-c_{v}=\dfrac{R}{M}

c_{p}=\dfrac{R}{M}+c_{v}

Where, c_{p} = specific heat at constant pressure

c_{v} = specific heat at constant volume

Put the value into the formula

c_{v}=\dfrac{8.314}{39.95}+0.3122

c_{v}=0.5203\ kJ/kg K

Hence, The specific heat of  argon at constant pressure is 0.5203 kJ/kg K.

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