The specific heat of hydrogen gas at constant pressure is C_(P)=3.4xx10^(3)"cal"//kg^(@)C and at constant volume is C_(V)=2.4xx10^(3)"cal"//kg^(@)C. If one kilogram hydrogen gas is heated from 10^(@)C to 20^(@)C at constant pressure the external work done on the gas to maintain it at cosntant pressure is
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Given :
Specific heat at constant pressure (Cp)= 3.4×10³ cal/kg°C
Specific heat at constant pressure (Cv) = 2.4×10³ cal/kg°C
Mass of hydrogen gas = 1kg
T₁ = 10°C = 283K
T₂ = 20°C = 293K
To Find :
The external work done on the gas
Solution :
- We know the relation Cp - Cv = R
R = 3.4×10³ - 2.4×10³
R = 1×10³cal/kg°C
- Work done = PΔV = mRΔT
= 1×1×10³×(293 -283)
= 10×10³ Cal
= 10⁴ Cal
The external work done on the gas is 10⁴ Cal
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