Physics, asked by SADDAaddayt, 9 months ago

The specific resistance σ of a thin wire of radius r cm, resistance R Ω and length L cm is given by σ = (πr^2R)/L.

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Answered by jana07122002

Answer:

The specific resistance σ of a thin wire of radius r cm, resistance R Ω and length L cm is given by σ = (πr^2R)/L. If r = 0.26 +/- 0.02 cm, R = 32 +/- 1 Ω and L = 78.00 +/- 0.01 cm, find the % error in σ.

Explanation:

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The specific resistance σ of a thin wire of radius r cm, resistance R Ω and length L cm is given by σ = (πr^2R)/L.​

Answers

The specific resistance σ of a thin wire of radius r cm, resistance R Ω and length L cm is given by σ = (πr^2R)/L.