The specific resistance of a wire is p, its volume is 3m^3, and its resistance is 3ohm. then what eill be its length?
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Answered by
13
resistance of wire = ρl/A
l = length of wire
A = area of wire
l x A = volume
so we can also write
R = ρl^2 / lA = ρl^2 / V
3 = ρl^2 /3
so l^2 = 9/ρ
so l = 3 / √ρ meter
i hope it will help you
regards
l = length of wire
A = area of wire
l x A = volume
so we can also write
R = ρl^2 / lA = ρl^2 / V
3 = ρl^2 /3
so l^2 = 9/ρ
so l = 3 / √ρ meter
i hope it will help you
regards
Rizvi1:
options. a) √ (1/p) b) 3/p c) √3 / p d) p √(1/3)
3 / √ρ is answer..bt tumhare otions se shi clarify nhi ho pa rha
tell me in english.. i dont knw hindi
3 / √ρ is answer...but by ur options don't clarify real otion ..may be u din't write..right option
d is correct option
if in question has 3 √ (1/p) like of option that will be correct option
Answered by
3
R = pL/A
To answer this question you should know above fromula.
Rearrange above equation to find L
L = RA / p
L = R × V/L × 1/p ……[∵ Area = Volume / Length]
L² = RV / p
L = √[(RV) / p]
= √[(3 Ω × 3 m³) / p]
= 3 / √p
Length of wire is 9 / √p
To answer this question you should know above fromula.
Rearrange above equation to find L
L = RA / p
L = R × V/L × 1/p ……[∵ Area = Volume / Length]
L² = RV / p
L = √[(RV) / p]
= √[(3 Ω × 3 m³) / p]
= 3 / √p
Length of wire is 9 / √p
options.. a) √(1/p) b) 3/p c) √3/ p d) p× √(1/p)
No option is correct.
Btw neglect the last line of my answer. I mistakenly wrote 9/√p instead of 3/√p
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