Question

the specific resistance of the materials of wire is 440 nano ohm m if the resistance of the wire is 14 ohm and diameter is 1 mm calculate the length of the wire​

Answer 1

$\rule{200}{2}$

$\huge\boxed{\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R:-}}}}}$

Given :

resistivity of the conductor = 44 * 10^-8 ohm m.

R = 14 ohm

Diameter = 1mm

Area = πD^2/4 = π/4 * (10^-3)^2 m^2

we know that,

length of wire = resistance * area/ resistivity of the conductor

=. 14 * π/4 * (10^-6)* 1/44*10^-8

= 14 * (22/7*4 )* 10^-6 *1/44*10^-8

= 14 * 22/28 * 100/44

= 22/2 * 100/44

= 100/4

= 25m

Answer 2

Answer:

Given :

resistivity of the conductor = 44 * 10^-8 ohm m.

R = 14 ohm

Diameter = 1mm

Area = πD^2/4 = π/4 * (10^-3)^2 m^2

we know that,

length of wire = resistance * area/ resistivity of the conductor

=. 14 * π/4 * (10^-6)* 1/44*10^-8

= 14 * (22/7*4 )* 10^-6 *1/44*10^-8

= 14 * 22/28 * 100/44

= 22/2 * 100/44

= 100/4

= 25m

Explanation:

hope it will help you. . . . . . . .

. . . haikhayya. .....