Chemistry, asked by sutharbhavnad, 5 months ago

The specific volumes of ice and water are 1.089 and 1.0 ml/ gm at 273 K temp. The molecular heat of fusion of ice is 6.025 kg/ mole at 273 K temp , then calculate the value of ∆H and ∆U for the process.

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Answered by bannybannyavvari

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The molecular heat of fusion of ice is 6.025 kg/ … ... fusion of ice is 6.025 kg/ mole at 273 K temp , then calculate the value of ∆H and ∆U for the ...

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The specific volumes of ice and water are 1.089 and 1.0 ml/ gm at 273 K temp. The molecular heat of fusion of ice is 6.025 kg/ mole at 273 K temp , then calculate the value of ∆H and ∆U for the process.​

Answers

The specific volumes of ice and water are 1.089 and 1.0 ml/ gm at 273 K temp. The molecular heat of fusion of ice is 6.025 kg/ mole at 273 K temp , then calculate the value of ∆H and ∆U for the process.