Question

The spee

d of two bikes is in the ratio 9:13
of bike a travels 615 km in 5 hro, then what
is the speed of Bike B?​

Answer 1

The speed of two bikes A and B is in the ratio 9:13. If bike A travels 615 km in five hours, then what is the speed of B?

Solution: A travels 615 km in 5 hours. So his speed = 615/5 = 123 km/hr.

The speed of B is (13/9) times that of A or (13*123)/9 = 177.7 km/hr. Answer

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Answer 2

Given:

The ratio of speeds to two bikes=9:13

To find:

The speed of the bike B

Solution:

Bike B's speed is 177.6 km/hr.

We know that an object's speed is obtained by dividing the distance covered by it and the time utilized.

So, bike A travelled 615km in 5 hours with the following speed-

Bike A's speed=615/5

=123 km/hr

Let the bike B's speed be B.

So, the speeds' ratio=123:B

On equating this with the given ratio, we get

123:B=9:13

123/B=9/13

123×13=9×B

123×13/9=B

177.6=B

Therefore, bike B's speed is 177.6 km/hr.