Question

the speed at the start of 10s is 10m/s and at the end it is 20m/s . Find the aceleration and distance travelled in the duration

Answer 1

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Answer 2

$\bold\red{\underline{\underline{Answer:}}}$

$\bold\green{\underline{\underline{Solution}}}$

$v = u + at$

(Newtons first equation of motion)

Here,

u=10m/s

v=20m/s

t=10s

To find: a

According to Newton's first equation of motion

20=10+a(10)

a(10)=10

a=1

a=1m/s^2

$s = ut + \frac{1}{2} \times a \times t {}^{2}$

Newtons second equation of motion

Here

u=10m/s

t=10s

a=10m/s^2

To find:s

According to newton's second equation of motion

s=10(10)+50

s=150m

$\bold\red{Acceleration \ is \ 10ms^{-2} \ and \ displacement \ is \ 150m}$