The speed at which an ant moves 3/4th of a circular track of radius 14cm in time 8secs is what??
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Answer:
radius of path = 14cm
time taken by the insect = 1minute = 60s
1. Distance covered = 2πr/2
=> πr
=> 22/7×14
=>44cm(0.44m)
2) Speed = Distance/time
=> 44/60
=>11/15
=>0.73cm/s or 0.0073m/s
3) Displacement = diameter of circle
=>2r
=>2×14cm
=>28cm or 0.28m
4)Average velocity=Displacement/time
=> 0.28/60
=>0.0047m/s or 47cm/s
5)It's velocity can be zero when its displacement will be zero.
That is if the insect moved back to it's initial position from where it started.
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Distance travelled by the ant = circumference × 3/4
radius, r = 14 cm
==> distance travelled = 2×22/7×14 × 3/4
==> distance travelled = 22 × 3
==> distance travelled = 66 cm
Time taken, t = 8 s
Speed = Distance / Time
==> 66/8
==> 33/4
==> 8.25 cm/s
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