Math, asked by ramesh9891957591, 1 year ago

The speed of a boat in still water is 10km/h if it can travel 26 km downstream and 14 km upstream in the same time find the speed of the stream

Answers

Answered by rakhich1978
2

Let the rate of the stream be x km/h.

The boat's rate when the river speeds up the boat by

adding its speed of x km/h to the boat's speed giving

10+x km/h.

The boat's rate when the river slows the boat down and

subtracts its speed of x km/h from the boat's speed

giving 10-x km/h.

Time = Distance/Rate

Downstream time = (Downstream Distance)/rate = 26/(10+x)

Upstream time = (Upstream Distance)/rate = 14/(10-x)

Those times are equal.

26/(10+x) = 14/(10-x)

Might as well divide both sides by 2

13/(10+x) = 7/(10-x)

Cross-multiply:

13(10-x) = 7(10+x)

130-13x = 70+7x

-20x = -60

x = 3 km/h

That's the answer. The rate of the river is 3 km/h. The story

is that he went down the river at 13 km/h for 26 km. for the

first 2 hours and came back at a slower 7 km/hr and only made

it 14 km of the way back when the second 2


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Answered by KSharma837
0

Let the speed of the stream be y km/hr

Upstream- (y-10) km/hr

Downstream- (y+10) km/hr

time= distance÷ speed

t= 26/(y+10) and t=14/(y-10)

solve and equate the above given equations

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