Question

the speed of a body as a function of time t is given by v=a+b+c/d^2+e+t.... what are the dimensions of a, b, c, d, e?​

Answer 1

Answer:

as the dimension of v=LT-¹

answer is

a=LT-¹

b=LT-²

c=L

d=T

Explanation:

Answer 2

Given,

v = a + b + $\frac{c}{d+t}$ + et

To find,

The dimension of a, b, c, d, and e.

Solution,

We may easily answer this numerical problem by following the steps below.

According to the idea of homogeneity, each term in a dimensional equation has the same dimensions on both sides. If this notion is followed, the provided equation will have the same dimension on both sides.

As a result, the dimensions of a and b will be the same as the velocity dimension.

a = [v] = LT⁻¹

b = [v] = LT⁻¹

The dimension of d will be equal to the dimension of time.

d = [T]

The dimension of c is now equal to the dimension of velocity multiplied by time.

c = [v][T]

c = [LT⁻¹][T]

c = [L]

The dimensions of e and c will be the same.

e = [L]

As a result, we can determine the dimension of all the unknown quantities in the equation in this manner.