Question

the speed of a body moving along a straight line path changes 5mper s3cond to 15 metre per second in 5 seconds.find the acceleration of the body​

Answer 1

initial Velocity = 5m/s (u)

finial velocity=15m/s (v)

Change in velocity= (15-5) m/s=10m/s. (∆)

time = 5s (t)

acceleration =? (a)

$\large\green{\boxed{a =\dfrac{ \triangle v}{t}}}$

=>$a = \dfrac{10ms^{-2}}{5}$

=>$a = 2ms^{-2}$

Therefore acceleration is 2m/s^2.