Question

The speed of a body moving along a straight path decreases from 10m/s to 5m/s in 2seconds . Find the deceleration​

Answer 1

Answer:

2.5m/s^2

Explanation:

U = 10m/s

V = 5m/s

T = 2s

declaration = V - U ÷ T

= 5-10÷2

= -5÷2

= 2.5

Note: you don't need to add negative signs when deceleration is mentioned in the question.

Answer 2

Give:

▪ Initial speed = 10mps

▪ Final speed = 5mps

▪ Time interval = 2s

To Find :

▪ Deceleration of body.

Concept:

Acceleration is defined as the rate of change in velocity(speed).

It is a vector quantity.

It can be positive, negative or zero.

It has both magnitude as well as direction.

SI unit: m/s²

Calculation:

v=u + at

5 = 10 + 2a

5-10 = 2a

2a = -5

a = -2.5

Acceleration = -2.5 m/s^2

Deceleration/Retardation = 2.5 m/s^2