The speed of a body of mass 4 kg increases from 2 m/s to 4 m/s in
a certain time interval. Find
the increase in the kinetic energy of the
body.
Answers
Answered by
5
Answer :
Mass of body = 4kg
Initial velocity = 2m/s
Final velocity = 4m/s
We have to find increase in the kinetic energy of body
Kinetic energy of body of mass m moving with velocity v is given by
- K = 1/2 × mv²
Let's calculate ☃
⇒ ΔK = Kf - Ki
⇒ ΔK = [1/2 × mv²] - [1/2 × mu²]
⇒ ΔK = m/2 × [v² - u²]
⇒ ΔK = 4/2 × [16 - 4]
⇒ ΔK = 2 × 12
⇒ ΔK = 24J :D
Answered by
4
Given ,
Mass (m) = 4 kg
Initial velocity (u) = 2 m/s
Final velocity (v) = 4 m/s
We know that , the kinetic energy of a body is given by
Where , v = velocity of body
Thus , the change in the kinetic energy will be
∆KE = 1/2 × 4 × (4)² - 1/2 × 4 × (2)²
∆KE = 4/2{16 - 4}
∆KE = 2 × 12
∆KE = 24 Joule
★ The increase in the kinetic energy of the body is 24 Joule ★
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