Physics, asked by vanditkejriwal2006, 9 months ago

The speed of a body of mass 4 kg increases from 2 m/s to 4 m/s in

a certain time interval. Find
the increase in the kinetic energy of the

body.​

Answers

Answered by Ekaro
5

Answer :

Mass of body = 4kg

Initial velocity = 2m/s

Final velocity = 4m/s

We have to find increase in the kinetic energy of body.

Kinetic energy of body of mass m moving with velocity v is given by

  • K = 1/2 × mv²

Let's calculate

⇒ ΔK = Kf - Ki

⇒ ΔK = [1/2 × mv²] - [1/2 × mu²]

⇒ ΔK = m/2 × [v² - u²]

⇒ ΔK = 4/2 × [16 - 4]

⇒ ΔK = 2 × 12

ΔK = 24J :D

Answered by Thelncredible
4

Given ,

Mass (m) = 4 kg

Initial velocity (u) = 2 m/s

Final velocity (v) = 4 m/s

We know that , the kinetic energy of a body is given by

 \boxed{ \sf{Kinetic  \: energy \:  (KE) =  \frac{1}{2}m {(v)}^{2}  }}

Where , v = velocity of body

Thus , the change in the kinetic energy will be

∆KE = 1/2 × 4 × (4)² - 1/2 × 4 × (2)²

∆KE = 4/2{16 - 4}

∆KE = 2 × 12

∆KE = 24 Joule

The increase in the kinetic energy of the body is 24 Joule

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