Question

The speed of a bullet of mass 20g is 216kmh–1. What is its k.E. in joules?

Answer 1

Answer:

mass of bullet. = 20g

v of bullet = 216 kmh-1

K.E = 1/2 m v^2

= 1/2 × 20 × 216

= 2160 kJ

= 2160

1000

= 2.16 J

Explanation:

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Answer 2

Hey guys your answer is here

$k .\: e. = \frac{1}{2} m {v}^{2}$

$\frac{1}{2} \times 20 \times 216 \\ = \frac{4320}{2} \\ = 2160kj \\ on \: dividing \: by \: 1000 \\ \frac{2160}{1000} = 2.16 \: joules$

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