the speed of a bus increase by 3km after every one hour .if the distance traveled in the first one hour was 45 km ,what was the total distance traveled in 15 hours
Answers
Answer:
AP:- 45, 93, 141, 189......upto 15 hrs
a=45
d=93-45=48
n=15
An=a+(n-1)d
An=45+ (15-1)48
An=45+ 14x48
An=45+ 672
An= 717
therefore, the total distance travelled in 15 hours is 717km
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Answer:
Total distance = 1305 km
Step-by-step explanation:
Given:
- Speed of the bus increases by 3 km ever one hour
- Distance travelled in the first hour = 45 km
To Find:
- Total distance travelled in 15 hours
Solution:
We know that,
Speed = Distance/Time
Hence,
Speed in the first hour is given by,
Speed = 45/1 = 45 km/hr
Given that speed increases by 3 km every hour
Hence speed in the successive hours is given by,
45, 48, 51.......
Now we have to find the total distance travelled in 15 hours.
For that we have to first find the speed at the 15th hour.
Since this follows an A.P, 15th term is given by,
a₁₅ = a₁ + 14d
a₁₅ = 45 + 14 × 3
a₁₅ = 45 + 42
a₁₅ = 87
Hence the speed at the 15th hour = 87 km/hr.
Now we know that,
Distance = Speed × Time
Substitute the data,
Distance = 87 × 15
Distance = 1305 km
Hence the total distance covered is 1305 km.