Question

The speed of a car increases from 10m/s square by 6m/s square in 10 second. what will be the acceleration?​

Answer 1

Answer:

0.4 m / sec² .

Explanation:

Given :

Initial velocity ( u ) = 6 m / sec .

Final velocity ( v ) = 10 m / sec .

Time ( t ) = 10 sec .

We have to find acceleration ( a ) .

We have :

v = u + a t

Putting values here we get :

10 = 6 + 10 a

10 a = 10 - 6

10 a = 4

a = 0.4 m / sec² .

Hence the acceleration of car is 0.4 m / sec² .

Answer 2

$\large{\mathfrak{\underline{\underline{Answer:-}}}}$

0.4 m/s²

${\mathfrak{\underline{\underline{Step-By-Step-Explanation:-}}}}$

$\mathrm{\underline{\gray{Given :-}}}$

Initial velocity (u) = 6m/s

Final velocity (v) = 10 m/s

Time (t) = 10s

__________________________

$\mathrm{\underline{\gray{To \: find :-}}}$

Acceleration

__________________________

$\mathrm{\underline{\gray{Solution :-}}}$

We have formula :-

$\huge{\bf{\boxed{\boxed{v \: = \: u \: + \: at}}}}$

________________[Put Values]

⇒ 10 = 6 + a * 10

⇒ 10 - 6 = 10a

⇒ 4 = 10a

⇒ a = 4/10

⇒ a = 0.4

$\large{\boxed{\boxed{\bf{a \: = \: 0.4 \: m/s^{2}}}}}$

$\rule{200}{2}$

$\large{\mathrm{\underline{\gray{Some \: Important \: Formulas:-}}}}$

• v = u + at

• s = ut + 1/2 * at²

• v² - u² = 2as

___________________

═══════❇☢☣⚛✳✴═══════

Where,

s is distance .

v is final velocity.

u is initial velocity .

a is acceleration .

t is time.

═══════❇☢☣⚛✳✴═══════