Question

The speed of a car is reduced from 100km/h to 7 km/h over a distance to 500m fluid uniform retardation and distance further travelled before coming to rest​

Answer 1

Answer:

The laws of physics are expressed in terms of physical quantities such as distance, speed, time, force ... Example 2.9 :A car A is travelling on a straight road with a uniform speed of 60 km h–1.

Answer 2

Answer:

initial speed u=100×5/18=27.7m/s

final speed v=7×5/18=1.9m/s

using v ^2=u^ 2 −2as, with a=500meter

we get a= 500×2

100−6.25

=0.3125m/s

2

now taking u=27.7m/s and v=0(rest) with a=0.3125 for the second case

we get s=

2×0.3125

6.25

=10meter