The speed of a car is reduced from 90 km/h to 36 km/h in 5 s.
What is the distance travelled by the car in this time interval ?
Answers
Answered by
0
Explanation:
(90-36)*(5/18)*5=ans
Answered by
0
Explanation:
u = 90 km/h
v = 36km/h
t= 5 s
a = v-u/t
a = 36 - 90 / 5
a = -54/5
a = -10.8
2as = v^2 - u^2
2 × 10.8 × s = 36^2 - 90 ^2
-21.6 s = 1296 - 8100
-21.6 s = -504
s = -504/-21.6
s = -525.6
hence,h
the distance travelled is -525.6 km.
hope it helps you....
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