The speed of a car is reduced from 90Km/
hr to 36Km/hr in 5 sec. What is distance
travelled by the car during this time interval?
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2
Answer:
35m
Explanation:
v=u+at
v=36*5/18
=10m/s
u=90*5/18
25m/s
10=25+a(5)
-15=5a
=>a=-3m/s^2
v^2-u^2=2as
s=100-625/2(-3)
-525/-15
35m
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