Question

The speed of a car is541/2km/hr.The distance traveled by it in 7/2 hours35/2minutes is.

Answer 1

$v = \frac{541}{2} \frac{km}{hr}$
$t = \frac{7}{2 } hr \: \frac{35}{2} min = \frac{91}{24} hr$
$v = \frac{s}{t}$
$s = vt$
$s = \frac{541}{2} \times \frac{91}{24}$
$s = 1025.6458$

Answer 2

Answer:

v = \frac{541}{2} \frac{km}{hr}v=

2

541

hr

km

t = \frac{7}{2 } hr \: \frac{35}{2} min = \frac{91}{24} hrt=

2

7

hr

2

35

min=

24

91

hr

v = \frac{s}{t}v=

t

s

s = vts=vt

s = \frac{541}{2} \times \frac{91}{24}s=

2

541

×

24

91

s = 1025.6458s=1025.6458