Question

the speed of a car weighing 3000N increases from 36 km/h to 72km/h uniformly. the change in momentum of the car is 3×10power x find x
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Answer 1

Answer:-

Given:

Weight of car (W) = 3000 N

We know that,

W = mg

where,

• m is mass

• g is acceleration due to gravity.

g on the earth is 9.8 m/s² ≈ 10 m/s².

So, m * 10 = 3000

⟶ m = 300 kg

Initial Velocity (u) = 36 km/h

• 1 km/h = 5/18 m/s.

⟹ u = 36 * 5/18 = 10 m/s

Final velocity (v) = 72 km/h

⟹ v = 72 * 5/18 = 20 m/s

Now,

Change in momentum (∆ P) = Final momentum (P_f) - Initial momentum(Pᵢ)

We know that,

• P = mass * velocity

⟶ ∆ P = mv - mu

⟶ ∆ P = (300)(20) - 300(10)

⟶ ∆ P = 6000 - 3000

⟶ ∆ P = 3000 kg.m/s

⟶ ∆ P = 3 × 10³ kg.m/s

∴ The value of x is 3.

Answer 2

Step-by-step explanation:

Always remember

chng in momentum = final - initial