Question

the speed of a cyclist decreases uniformly from 20 m/s to 10 m/s in 12 seconds.
i. Calculate deceleration of the cyclist.
ii. Calculate distance traveled by the cyclist during this time.

Answer 1

Answer:

1) Deceleration:

Final velocity - initial velocity / amount of time taken for the drop in velocity

= 10 - 20 / 12

= -10 / 12

= 0.833 m/s2

2) Distance travelled by cyclist:

D = u/v * t/2 (u= initial vel, v= final velocity)

= 20 / 10 * 12 / 2

= 2 * 6

= 12 m