Question

The speed of a cyclist reduces uniformly from 2.5m/s to 1.0m/s in 12s. Calculate the deceleration of the cyclist and calculate the distance travelled by the cyclist in this time

Answer 1

Answer:

Accelaration=F.V-I.V/TIME TAKEN

NOW WE CAN SAY THAT,

a=0-2.5/12

a=-2.5/12

a=0.2083

Acceleration or deceleration = Final velocity - initial velocity / Time taken

D = 1-2.5 / 12

D= -0.125

d = ½×(Vi + Vf) × t

where

d = displacement = ?

Vf = final velocity = 1 m/s

Vi = initial velocity = 2.5 m/s

t = time = 12 s

so

d = ½×(2.5 + 1) × 12

d = 21 m