Question

The speed of a homogenous solid sphere after rolling down an
inclined plane of vertical height h from rest without sliding is
(a)√10 gh (b) √gh
7
(c)√ 6 gh (d) √4 gh
5 3

Answer 1

Answer:

For solid sphere I=

5

2

mR

2

Work- energy theorem, mgh=

2

1

Iw

2

+

2

1

mv

2

mgh=

2

1

×

5

2

mR

2

w

2

+

2

1

mv

2

where v=Rw (due to pure rolling)

⟹v=

7

10