Question

The speed of A is twice that of B. The speed of B is 3 times that of C. C Takes 48 minutes to complete the journey. Then how many minutes does A take to complete the journey?

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Answer 1

$\color{red}\huge{\underline{\underline{GIVEN\dag}}}$

• Speed of "A" is twice that of "B".
• Speed of "B" 3 times that of "C".
• "C" takes 48 min to complete the journey.

$\color{red}\huge{\underline{\underline{SOLUTION\dag}}}$

$Speed_{B}=3×Speed_{C}$

We know that;

$\color{blue}{\boxed{Speed=\frac{Distance}{Time}}}$

And;

$Distance travelled by 'A' 'B' & 'C' is equal$

$\frac{Distance}{Time_{B}}=3×\frac{Distance}{Time_{C}}$

$\frac{1}{Time_{B}}=\frac{3}{48}$

${Time_{B}}=\frac{48}{3}$

${Time_{B}}=16mins$

But;

$Speed_{A}=2×Speed_{B}$

$\frac{Distance}{Time_{A}}=2×\frac{Distance}{Time_{B}}$

$\frac{1}{Time_{A}}=\frac{2}{16}$

${Time_{A}}=\frac{16}{2}$

$\color{orange}{\boxed{\therefore{Time_{A}}=8mins}}$

HOPE THAT HELPS!!