Math, asked by aryangupta6262, 9 months ago

the speed of a moving car is tripled the distance travelled by it before coming to rest as compared to earlier will be
(a) three times (b) six times

(c)nine times (d) twelve times​

Answers

Answered by topwriters
2

The distance traveled will be 9 times than earlier if speed is tripled.

Step-by-step explanation:

From the third equation of motion, we know that:

v² = u² + 2as

where u and v are the initial and final velocity, a is the acceleration and s is the distance.

If final velocity v = 0, then the equation will become:

u = √2as

​Now given that the speed has tripled, then we find that the distance should be 9 times in order to balance the equation.

 3u = √(2as*9)

Option C is the answer.

Answered by trilokipy2010
1

nine time

v^2=u^2-2a (Retardation)

0=u^2-2as

S=u^2/2a

1st case_s1=u^2/2a

2nd case _s2= (3u)^2/2a

=9^u^2/2a

=9^s1 answer

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