Question

the speed of a projectile at its maximum height is 6m/s. IFthe air for a long time of 8secs,its horizontal range is​

Answer 1

Answer:

The projectile would move with its horizontal component of velocity v0 cosθ = 6ms-1 in all its trip. The time it stays in space is 8 sec. Thus the horizontal range it would cover is 8 sec x 6ms-1 = 48 m.