Question

the speed of a projectile at its maximum height is 6m/s. if it stays in the air for a total time of 8 seconds, its horizontal Range is​

Answer 1

Answer:

'The 'speed of a projectile' at its 'maximum height' is 6m/s'. If it stays in the air for a total time of 8 seconds, its horizontal range is in the 'horizontal direction'.

Explanation:

The projectile would move with its horizontal component of velocity v0 cosθ = 6ms-1 in all its trip.

The time it stays in space is 8 sec. Thus the horizontal range it would cover is 8 sec x 6ms-1 = 48 m.

So it is the horizontal range.

Answer 2

Explanation:

u=6m/s

the object remains in air for 8s

therefore the time of flight=8

t=2u sin theta/g

8=2×6 sin theta/10

80/16=sin theta

sin theta=20/3

Range=u^2 sin2 theta/g

=36×40/3/10

=12×40/10

48 m

horizontal range =48 m

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