Question

the speed of a projectile at its maximum height is half of its initial Speed the angle of projection is ?​

Answer 1

Answer:

angle of projection = 60°

Explanation:

A/c to question,

u cos(theta) = u/2

=> cos(theta) = 1/2

=> theta = 60°

so, angle of projection = 60°

hope, it helps you.

Answer 2

At the topmost position, only horizontal velocity exists. Thus,

$\displaystyle\longrightarrow\sf{u\cos\theta=\dfrac{u}{2}}$

$\displaystyle\longrightarrow\sf{\cos\theta=\dfrac{1}{2}}$

$\displaystyle\longrightarrow\sf{\theta=60^o}$