Physics, asked by mmehak4986, 1 year ago

The speed of a projectile at its maximum height is root 3 by 2 times its initial speed its range on the horizontal plane is

Answers

Answered by vimalraj1217
0

Answer:

UCosx = sqrt(3)/2 * u

Cosx = sqrt(3)/2

x = 30°

R = u^2 Sin(2x) / g

= u^2 Sin(60) / g

= (u^2 / g) * [sqrt(3)/2]

Range of the projectile is (u^2 / g) * [sqrt(3)/2]

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