Math, asked by Manshi9984, 6 months ago

The speed of a river current is 3 km/h A boat takes the same time to travel 15km upstream as it does to travel 18 km downstream . Find the speed of the boat in still water.

Answers

Answered by Anonymous
15

\blue{\bold{\underline{\underline{Answer:}}}}

 \:\:

 \green{\underline \bold{Given :}}

 \:\:

  • The speed of a river current is 3 km/hr

 \:\:

  • A boat takes the same time to travel 15 km upstream as it does to travel 18 km downstream

 \:\:

 \red{\underline \bold{To \: Find:}}

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  • Speed of the boat in still water.

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\large{\orange{\underline{\tt{Solution :-}}}}

 \:\:

Let the speed of boat in still river be 'x'

 \:\:

 \underline{\bold{\texttt{Speed in upstream :}}}

 \:\:

\purple\longrightarrow  \sf x - 3

 \:\:

 \underline{\bold{\texttt{Speed in downstream :}}}

 \:\:

\purple\longrightarrow  \sf x + 3

 \:\:

 \red{\bold{We \: know \: that :}}

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 \rm \dag \: \: Speed \: = \: \dfrac { Distance } { Time }

 \:\:

 \purple{\bold{Let \: time \: for \: downstream \: be \: 't1' </p><p>}}

 \purple{\bold{Let \: time \: for \: upstream \: be \: 't2' }}

 \:\:

 \huge \sf For \: upstream

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 \rm\dashrightarrow (x - 3) = \dfrac { 15 } { t1 }

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 \bf\longmapsto t1 = \dfrac { 15 } { x - 3 }

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 \huge \sf For \: downstream

 \:\:

 \rm\dashrightarrow (x + 3) = \dfrac { 18 } { t2 }

 \:\:

 \bf\longmapsto t2 = \dfrac { 18} { x + 3 }

 \:\:

 \purple{\bold{We \: know \: that \: t1\: = \: t2}}

 \:\:

 \sf \longmapsto \dfrac { 18 } { x + 3 } = \dfrac { 15 } { x - 3 }

 \:\:

 \sf \longmapsto 18x - 54 = 15x + 45

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 \sf \longmapsto 18x - 15x = 45 + 54

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 \sf \longmapsto 3x = 99

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 \sf \longmapsto x = \dfrac { 99 } { 3 }

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 \bf \dashrightarrow x = 33

 \:\:

Hence speed of boat in still water is 33 km/hr

\rule{200}5

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