Question

The speed of a satellite in an orbit at
a height of 1000 km from the earth's
surface is
(Given: Mass of
earth = 5.98 x 1024 kg, Radius of earth
= 6.4x 106 m, g=9.8 m/s2) *​

Answer 1

Answer: 7333.74m/s

Explanation:

Let radius of the earth be R, universal gravitational constant be G, mass of the earth be M, height of the satellite from the earth surface be H, orbital speed of the satellite be V.

We know G = 6.67×10^-11

Therefore

V=√{(G×M)/(R+H) }

=√{3.98×10^14/7400000}

=7333.74m/s