Question

The speed of a train
decrease from 72 km/h to 54 km/h in 5 seconds .
find the acceleration of the train SI unit?​

Answer 1

GiveN :

• Initial velocity (u) = 72 km/h = 20 m/s
• Final velocity (v) = 54 km/h = 15
• Time (t) = 5 s

To FinD :

• Acceleration of train

SolutioN :

⇒a = (v - u)/t

⇒a = (15 - 20)/5

⇒a = -5/5

⇒a = -1

Acceleration is -1 m/s².

Answer 2

Answer:

-1m/s^2

Explanation:

u=72km/h= 72×5/18= 20m/s

v=54km/h= 54×5/18 =15m/s

t=5sec.

We know that,

a=v-u/t

a=(15-20)/5

a= (-5)/5

【a= -1 m/s²】