Question

The speed of a vehicle of mass 500 kg increase from 36 km/h to 72 km/h calculate the increase in its k.e

Answer 1

Heya user,

Consider the initial Kinetic energy -->
It is ---> 1/2 m $v_1$² = 1/4 * 1000 * 36²

Changed Kinetic energy ---> 1/4 * 1000 * 72²

.'. The increase is [ 1/4 * 1000 * 72² ] - [ 1/4 * 1000 * 36² ] 
=============> 1/4 * 1000 [ 5184 - 1296 ] = 3888 / 4 * 1000 = 972 000

Hence, the increase is 972 kilojoules