The speed of a vehicle of mass 500 kg increases from 36km/hr to 72 km/hr .calculate the increase in its kinetic energy
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Answer:
75000 J or 75 kJ
Explanation:
Given:-
u= 36 km/h=10 m/s
v=72 km/h = 20 m/s
m= 500 kg
K.E.= ?
Formula:-
Change in K.E.= 1/2*m*(v^2-u^2)
Solution:-
Change in K.E.= 1/2*500*(20^2-10^2)
= 250(400-100)
= 250*300
= 75000 J or 75 kJ
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