Question

The speed of a wave is 360m/s and is 500Hertz if the phase difference of two neighbouring particles is 60 degree then what will be path difference?​

Answer 1

Answer:

6/25 metres

Explanation:

v=360

f=500

so wavelength, l=v/f=

$\frac{360}{500} = \frac{18}{25}$

so, for 180 degree of phase difference, path difference

$= \frac{18}{25}$

for 1 degree of phase difference, path difference=

$\frac{18}{25} \times \frac{1}{180}$

for 60 degree of phase difference, path difference=

$\frac{18}{25} \times \frac{1}{180} \times 60$

$= \frac{18}{25} \times \frac{1}{3 }$

$= \frac{6}{25} metres$