Physics, asked by arideepa19, 5 months ago

the speed of a weighting car is 3000N Increases fron 36 km\h to 72 km\h uniformly . The change in momentum of the car is 3x10^x kg-m\s. Then x is

Answers

Answered by amit7748
1

Answer:

x=3

Explanation:

36km\h =10m/s

73km/h =20m/s

weight of car is 3000N so

weight=mass×accelaration due to gravity

w=mg

m=w/g (g=10m/s^-2)

=3000/10=300kg

momentum is given by

p=mv

so when v=10 then

p1=300×10=3000kgm/s

p2=300×20=6000kgm/s

change in momentum

p2-p1=6000-3000

=3000kgm/s=3×10^3kgm/s

so Comparing with 3×10^x kg m/s

x=3

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