The speed of a wheel increases from 100 rpm to 1200 rpm in 20s ,what is its angular acceleration? how many revolutions will it make during this time
Answers
Answered by
2
use angular kinematic equation ,
w=wo +at
where w is final angular velocity
wo is initial ,, ,, ,,
and a is angular acceleration.
now,
1200/60 rps-100/60 rps =20.a
1100/60 =20 a
a =1100/3 r p s^2
w^2=wo^2+2a@
where @ is no of revolution
(1200/60)^2-(100/60)^2=2 x 1100/3 x @
(1440000-10000)/3600=2200/3 @
14300/36= 2200/3 @
143/(22 x 12) = @
w=wo +at
where w is final angular velocity
wo is initial ,, ,, ,,
and a is angular acceleration.
now,
1200/60 rps-100/60 rps =20.a
1100/60 =20 a
a =1100/3 r p s^2
w^2=wo^2+2a@
where @ is no of revolution
(1200/60)^2-(100/60)^2=2 x 1100/3 x @
(1440000-10000)/3600=2200/3 @
14300/36= 2200/3 @
143/(22 x 12) = @
Similar questions