Question

The speed of a wooden toy car of mass 5 kg changes from 3 m/s to 12 m/s in 3 seconds. Calculate the applied force. answer the questions ​

Answer 1

F= M (12-3/3)

F= 5kg × 3m/s^2

F= 5×3= 15N

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Answer 2

Answer:

given data

V1=3m/s

V2=12m/s

time interval t= 3s

f=?

m=5 jg

Explanation:

f=mv

• F1 = mv1/t

F1= 5×3/3=15/3N

• F1=5N
• F2=mv2

F2=5×12/3=60/3

• F2= 20N

Fm= F1 ×F2)t

Fm= (5×20)/3

Fm= 100/3= 33.3N

F=33.3N