The speed of a wooden toy car of mass 5 kg changes from 3 m/s to 12 m/s in 3 seconds. Calculate the applied force. answer the questions
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Answered by
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F= M (12-3/3)
F= 5kg × 3m/s^2
F= 5×3= 15N
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Answered by
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Answer:
given data
V1=3m/s
V2=12m/s
time interval t= 3s
f=?
m=5 jg
Explanation:
f=mv
- F1 = mv1/t
F1= 5×3/3=15/3N
- F1=5N
- F2=mv2
F2=5×12/3=60/3
- F2= 20N
Fm= F1 ×F2)t
Fm= (5×20)/3
Fm= 100/3= 33.3N
F=33.3N
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