Question

The speed of an airplane is 1,240 km per hour. Find the distance covered by the airplane
in 3 hours and 20 minutes. Also, express the distance in scientific notation.

Answer 1

Step-by-step explanation:

The above question was the formula of:-

distance=speed×time

all the units in the above formula must be in their same units .

so the given values are

speed =1240km/he

time= 3 hrs 20 minutes= 3*1/3=10/3hrs.

so now the new unit are ready for operation.

applying the distance,time and speed formula:-

we get-

• distance =1240×10/3km

=413•3333×10

=414•33×10

=4•1333×10to the power 3 , which is a scientific notation...

Answer 2

$\sf\huge\bold{Answer:}$

Given :

speed of an airplane = 1240 km/h

Time=3hrs20min

To find :

Distance covered by plane

Solution :

$\fbox{Formula used :}$

$\tt\red{ :⟶distance = speed \times time}$

Speed=1240km/h

Time=3hr+20min

[1min=1/60hr]

=3hr+(20/60)hr

=3hr+⅓hr

=3⅓hr

Inserting values in formula :

$\tt\ :⟶d = \big(1240\times 3 \frac{1}{3} \big)km$

Converting mixed fraction into improper fraction

$\tt\ :⟶d = 1240 \times \frac{3 \times 3 + 1}{3} \: \: \: km$

$\tt\ :⟶d = \big(1240 \times \frac{10}{3} \big)km$

$\tt\ :⟶d = \big( \frac{12400}{3} \big)km$

$\tt\ :⟶d = 4133.33...km$

$\tt\ :⟶d ≈ 4133.3km$

Distance covered by plane is 4133.3km

Converting distance in scientific notation

$\tt\ :⟶d = 4133.3 \times \frac{1000}{1000} \\ \:$

$\tt:⟶d=4.1333\times 10 {}^{3}$

$\tt:⟶d=4.13\times 10 {}^{3}$

$\tt\purple{d=4.13 \times 10 {}^{3} }$

Distance covered by plane is 4.13×10³ km