The speed of an electron in the second orbit of hydrogen atom is
Answers
Answered by
5
In general the velocity of an electron in the nth orbit in any element is
Vn = z/n (Vо)
where Z is the atomic number of the element, n is the principal quantum number of the orbit in which the electron is and Vο is a constant equal to 2.19 * 10^6 m/s.
so in the second orbit of hydrogen, V=(2.19*10^6)*1/2=1.095*10^6 m/s
Vn = z/n (Vо)
where Z is the atomic number of the element, n is the principal quantum number of the orbit in which the electron is and Vο is a constant equal to 2.19 * 10^6 m/s.
so in the second orbit of hydrogen, V=(2.19*10^6)*1/2=1.095*10^6 m/s
Similar questions
Hindi,
8 months ago
Computer Science,
8 months ago
Science,
8 months ago
Science,
1 year ago
Science,
1 year ago