Question

The speed of an electron increases from 1.8x10 m/s to 24 x 10 m/s. Calculate the amount of work done to increase the speed.

Answer 1

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Answer 2

The amount of work done to increase the speed is $1.14\times 10^{-14}\ J$.

Explanation:

Given that,

Initial speed of the electron, $u=1.8\times 10^8\ m/s$

Final speed of the electron, $v=2.4\times 10^8\ m/s$

To find,

The amount of work done to increase the speed.

Solution,

We know that the mass of the electron is, $m=9.1\times 10^{-31}\ kg$

The work energy theorem states that the work done by the object is equal to the change in its kinetic energy as :

$W=\dfrac{1}{2}m(v^2-u^2)$

$W=\dfrac{1}{2}\times 9.1\times 10^{-31}\times ((2.4\times 10^8)^2-(1.8\times 10^8)^2)$

$W=1.14\times 10^{-14}\ J$

So, the amount of work done to increase the speed is $1.14\times 10^{-14}\ J$. Hence, this is the required solution.

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