The speed of an object at the end of 4 successive seconds is 20, 25, 30, and 35 mi/hr, respectively. Th acceleration of this object is
Answers
Answer:
The answer is 5 m/s.
apply the kinematics formula: V (final in m/s) = V (initial in m/s) + A (in m/s^2) *T (in [s]
the intial of 20 m/s and the final of 25 m/s
25 = 20 + A(m/s^2)T(s)
T = 1 second (The interval in which this change in velocity occurred)
25 = 20 + A(1)
25 = 20 + A
A = 5 m/s^2
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Answer:
0.0014 m/s
Explanation:
The increase in speed per successive second = (v - u)
1) 25 - 20 = 5m/h
2) 30 - 25 = 5m/h
3) 35 - 30 = 5m/h
As we see the speed change is same , hence the acceleration is constant.
For the next we'll need to covert the given speeds into m/s (standard unit)
v - u = 5m/h = 5 / 3600 = 0.00138 m/s ≈ 0.0014 m/s
now,
Acceleration = (v-u) / t =0.0014/ 1 = 0.0014 m/s²
(as the change occurs every one second :> time = 1 sec )