The speed of B is 20% more than the speed of A. If A covers distance in 20 minutes then B will cover that distance
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s=d/t
let distance be x
speed of a =x/20
speed of b is 20 percent more than a
speed of b= 20/100 X x/20 + x/ 20
= 3x/50
3x/50=x/t
t =50/3 minutes
16.667 minutes
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