Question

the speed of body decrease from 120m/s to 54km/h in ten seconds calculate acceleration in m/s² and displacement is km​

Answer 1

Initial speed(u)=120m/s

Final speed(v)=54km/h=54*5/18

= 15m/s

Time(t)=10s

$a = \frac{v - u}{t}$

a=120-15/10

=105/10

=10.5 m/s^2

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Answer 2

Answer:-

• Initial velocity=120m/s=u
• Final velocity=v=54km/h

Convert it to m/s

$\\ \tt\longmapsto 54\times \dfrac{5}{18}$

$\\ \tt\longmapsto 15m/s$

• Time taken=t=10s

We know that

$\boxed{\sf Acceleration=\dfrac{v-u}{t}}$

$\\ \tt\longmapsto Acceleration=\dfrac{15-120}{10}$

• Body retards here

$\\ \tt\longmapsto Retardation=\dfrac{-105}{10}$

$\\ \tt\longmapsto Reatrdation=-10.5m/s^2$