Question

The speed of bus increases by 3km after every one hour. If
The distance travel in first
hour was
45 km
What was total distance
travelled in 15 hours
​

Answer 1

Answer:

This answer can be solved with Arithmetic Progression method..

Distance travelled in 1st hour=26

Speed increases by 3 km/hr so next hour distance travelled would be 29 and so on ….

So the figures would be 26 29 32….

No. Of. Hours =12

We can apply the sum of A.P formula =n/2(2a+(n-1)d)

Where n=12,a=26,d=3

Thus we get ,Total distance = 6(52+33)=510 km(Answer)

Answer 2

Answer:

The total distance travelled by bus in 15 hours is equal to 1305 km.

Step-by-step explanation:

Given, the speed of the bus increases by 3 km after every 1 hour.

and, the distance travelled in the 1st hour = 45 km

We know that, Speed = distance/time

Speed in the first hour will be equal to, Speed = 45/1 = 45 km/hr

As given in the question, that speed increases by 3 km after every hour.

The speed of bus in the successive hours will be: 45, 48, 51,.........

To calculate the speed at the 15th hour:-

The obtained series is A.P, so the 15th term will be:-

$a_{15}= a_1 + 14d\\a_{15} = 45 + 14 \times 3\\a_{15} = 45 + 42\\a_{15} = 87$

Therefore, the speed of bus at the 15th hour =$87 km/hr.$

From the formula of speed, distance = speed × time

$Distance = 87 \times 15\\Distance = 1305 km$

Hence, the total distance covered by the bus is equal to 1305 km.

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