the speed of car changes from 36 km per hour to 72 km per hour in 10 seconds if mass of car is 500 kg then find (1)acceleration (2)force on car (3) in the its kinetic energy
Answers
Answered by
1
initial speed of car(u)=36km/hr=10m/s
final speed of car(v)=72km/hr=20m/s
time taken(t)= 10s
therefore,
(1.) acceleration=(v-u))t=(20-10)/10=1m/s*2
(2.) force=mass*acceleration
=500*1=500N
(3.) initial kinetic energy=MU*2/2=500*100/2=25000J
Final kinetic energy= MV*2/2=500*400/2=100000J
final speed of car(v)=72km/hr=20m/s
time taken(t)= 10s
therefore,
(1.) acceleration=(v-u))t=(20-10)/10=1m/s*2
(2.) force=mass*acceleration
=500*1=500N
(3.) initial kinetic energy=MU*2/2=500*100/2=25000J
Final kinetic energy= MV*2/2=500*400/2=100000J
Similar questions
Computer Science,
7 months ago
Math,
7 months ago
Physics,
7 months ago
Chemistry,
1 year ago
Political Science,
1 year ago
Environmental Sciences,
1 year ago