Question

The speed of car is redused from 108km/hr to 36 km/hr in 4.0 sec find its acceleration and distance travelled by car during this time interval

Answer 1

u = 30 m/sec
v = 10 m/sec
t = 4
a = ?

v = u + at
10 = 30 + a4
-20 = 4a
-20/4 = a
-5m/s^2 = a (Retardation)

Answer 2

u=108 kmph = 30 m/s

v=36 kmph = 10 m/s

a =v-u/t = 30- 10/ 4 =5 m/s^2

s= ut + 1/2 at^2

   40 + 40 = 80m